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Q.) A force acts on a 30 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t^2 + t^3, where x is in metres and t is in seconds. The work done during the first 4 seconds is:
[A]5.28 J
[B]450 J
[C]490 J
[D]530 J