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Q.) A circle of constant radius 'a' passes through origin O and cuts the axes of co-ordinates in points P and Q, then the equation of the locus of the foot of perpendicular from O to PQ is
[A]
(x² + y²)(1/x² + 1/y²) = 4a²
[B]
(x² + y²)^2(1/x² + 1/y²) = 4a²
[C]
(x² + y²)(1/x² + 1/y²) = 4a²
[D]
(x² + y²)(1/x² + 1/y²) = a²
[A] (x² + y²)(1/x² + 1/y²) = 4a²
[B] (x² + y²)^2(1/x² + 1/y²) = 4a²
[C] (x² + y²)(1/x² + 1/y²) = 4a²
[D] (x² + y²)(1/x² + 1/y²) = a²
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