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Q.) If point A is (1, 0) and point B is (0, 1). If point C is on the circle x² + y² = 1, then the locus of the orthocentre of the triangle ABC is
[A]x² + y² = 4
[B]x² + y²- x - y = 0
[C]x² + y² - 2x - 2y + 1 = 0
[D]x² + y² + 2x - 2y + 1 = 0